2x^4+7/2x^2-1=0

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Solution for 2x^4+7/2x^2-1=0 equation:


x in (-oo:+oo)

2*x^4+(7/2)*x^2-1 = 0

2*x^4+7/2*x^2-1 = 0

t_1 = x^2

2*t_1^2+7/2*t_1^1-1 = 0

2*t_1^2+7/2*t_1-1 = 0

DELTA = (7/2)^2-(-1*2*4)

DELTA = 81/4

DELTA > 0

t_1 = ((81/4)^(1/2)-7/2)/(2*2) or t_1 = (-(81/4)^(1/2)-7/2)/(2*2)

t_1 = 1/4 or t_1 = -2

t_1 = -2

x^2+2 = 0

1*x^2 = -2 // : 1

x^2 = -2

t_1 = 1/4

x^2-1/4 = 0

1*x^2 = 1/4 // : 1

x^2 = 1/4

x^2 = 1/4 // ^ 1/2

abs(x) = 1/2

x = 1/2 or x = -1/2

x in { 1/2, -1/2 }

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